Question

Expand : ${\displaystyle (3a+\frac{2}{b})(2a-\frac{3}{b})}$

Answer 1

${\displaystyle (3a+\frac{2}{b})(2a-\frac{3}{b})=\left(3a\right)\left(2a\right)+\left(\frac{2}{b}\right)\left(2a\right)-\left(\frac{3}{b}\right)\left(3a\right)-\left(\frac{2}{b}\right)\left(\frac{3}{b}\right)}$

= ${\displaystyle 6a^2+(\frac{4}{b}-\frac{9}{b})a-\frac{6}{b^2}}$

= ${\displaystyle 6a^2+(-\frac{5}{b})a-\frac{6}{b^2}}$

= ${\displaystyle 6a^2-\frac{5a}{b}-\frac{6}{b^2}}$