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Question
Expand (ab – c)3
Sum
Solution
(ab – c)3
Comparing (ab – c)3 with (a – b)3 we have a = ab and b = c
(a – b)3 = a3 – 3a2b + 3ab2 – b3
(ab – c)3 = (ab)3 – 3(ab)2c + 3ab(c)2 – c3
= a3b3 – 3(a2b2)c + 3abc2 – c3
= a3b3 – 3a2b2c + 3abc2 – c3
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Chapter 3: Algebra - Exercise 3.3 [Page 91]
