Advertisements
Advertisements
Question
Explain Mendel’s dihybrid ratio with the help of any one cross.
Solution 1
- In the dihybrid cross, two pairs of contrasting characteristics are under consideration.
- Mendel performed more experiments on hybridization in which he considered more than one pair of contrasting characteristics. He brought about a cross between a pea plant producing rounded and yellow coloured seeds and a pea plant with wrinkled and green coloured seeds. In this cross, two pairs of contrasting characteristics were considered colour of seeds and shape of seeds. Hence, it is called a dihybrid cross.
- Parental generation (P1): Mendel selected the pea plants producing rounded yellow seeds and wrinkled green seeds as parent plants, as shown in the chart. During gamete formation in P1 generation, the pair of gametes separate independently i.e. in RRYY plants, only RY type gametes are formed and not RR and YY. Similarly, in rryy plants, only ry gametes are formed. Thus we can say that each pair of genes is represented in the gamete by only one gene from that pair.
- Based on the conclusions from the monohybrid cross, Mendel expected that in the F2 generation of dihybrid cross, plants would produce rounded-yellow seeds. He was proved right. Though the genotype of these plants was RrYy, their phenotype was like the parents producing rounded-yellow seeds, because yellow colour is dominant over green and round shape is dominant over wrinkled. Due to the combination of two different characteristics in the F1 generation of the dihybrid cross, these plants are called dihybrid plants.
- Plants of the F1 generation of dihybrid cross produce four types of gametes RY, Ry, rY, ry. Of these gametes, RY and ry are similar to those of the P1 generation. The 16 different possible combinations through the union of 4 types of male gametes and 4 types of female gametes.
Mendel’s experiment of dihybrid cross | ||||
Parental Generation P1 | ||||
Phenotype | Rounded-yellow seeds | Wrinkled-green seeds | ||
Genotype | RRYY | rryy | ||
Gametes | RY | ry | ||
First Filial Generation F1 | RrYy | |||
(Rounded-yellow seeds) | ||||
Phenotype P2 | Selfing in F1 | |||
Phenotype | Rounded-yellow seeds | Rounded-yellow seeds | ||
Genotype | RrYy | RrYy | ||
Gametes | RY, Ry, rY, ry |
RY, Ry, rY, ry |
||
Second Filial Generation F2 |
|
|||
Male gamete/Female gamete | RY |
Ry |
rY | ry |
RY | RRYY |
RRYy |
RrYY | RrYy |
Ry | RRYy |
RRyy |
RrYy | Rryy |
rY | RrYY |
RrYy |
rrYY | rrYy |
ry | RrYy |
RrYy |
rrYy | rryy |
- The proportions obtained in the F2 progeny generation formed from the dihybrid experiment are as follows:
- Phenotypic ratio = 9 : 3 : 3 : 1
- Round-Yellow: 9
- Wrinkled-Yellow: 3
- Round-Green: 3
- Wrinkled-Green: 1
- Genotypic ratio: = 1 : 1 : 2 : 2 : 4 : 2 : 2 : 1 : 1
RRYY = 1, RRyy = 1, RRYy = 2, RrYY = 2, RrYy = 4, Rryy = 2, rrYy = 2, rrYY = 1, rryy = 1
Solution 2
- In the dihybrid cross, two pairs of contrasting characteristics are under consideration.
- Mendel performed more experiments on hybridization in which he considered more than one pair of contrasting characteristics. He brought about a cross between a pea plant producing rounded and yellow coloured seeds and a pea plant with wrinkled and green coloured seeds. In this cross, two pairs of contrasting characteristics were considered colour of seeds and shape of seeds. Hence, it is called a dihybrid cross.
- Parental generation (P1): Mendel selected the pea plants producing rounded yellow seeds and wrinkled green seeds as parent plants, as shown in the chart. During gamete formation in P1 generation, the pair of gametes separate independently i.e. in RRYY plants, only RY type gametes are formed and not RR and YY. Similarly, in rryy plants, only ry gametes are formed. Thus we can say that each pair of genes is represented in the gamete by only one gene from that pair.
- Based on the conclusions from the monohybrid cross, Mendel expected that in the F2 generation of dihybrid cross, plants would produce rounded-yellow seeds. He was proved right. Though the genotype of these plants was RrYy, their phenotype was like the parents producing rounded-yellow seeds, because yellow colour is dominant over green and round shape is dominant over wrinkled. Due to the combination of two different characteristics in the F1 generation of the dihybrid cross, these plants are called dihybrid plants.
- Plants of the F1 generation of dihybrid cross produce four types of gametes RY, Ry, rY, ry. Of these gametes, RY and ry are similar to those of the P1 generation. The 16 different possible combinations through the union of 4 types of male gametes and 4 types of female gametes.
Mendel’s experiment of dihybrid cross | ||||
Parental Generation P1 | ||||
Phenotype | Rounded-yellow seeds | Wrinkled-green seeds | ||
Genotype | RRYY | rryy | ||
Gametes | RY | ry | ||
First Filial Generation F1 | RrYy | |||
(Rounded-yellow seeds) | ||||
Phenotype P2 | Selfing in F1 | |||
Phenotype | Rounded-yellow seeds | Rounded-yellow seeds | ||
Genotype | RrYy | RrYy | ||
Gametes | RY, Ry, rY, ry |
RY, Ry, rY, ry |
||
Second Filial Generation F2 |
|
|||
Male gamete/Female gamete | RY |
Ry |
rY | ry |
RY | RRYY |
RRYy |
RrYY | RrYy |
Ry | RRYy |
RRyy |
RrYy | Rryy |
rY | RrYY |
RrYy |
rrYY | rrYy |
ry | RrYy |
RrYy |
rrYy | rryy |
- The proportions obtained in the F2 progeny generation formed from the dihybrid experiment are as follows:
- Phenotypic ratio = 9 : 3 : 3 : 1
- Round-Yellow: 9
- Wrinkled-Yellow: 3
- Round-Green: 3
- Wrinkled-Green: 1
- Genotypic ratio: = 1 : 1 : 2 : 2 : 4 : 2 : 2 : 1 : 1
RRYY = 1, RRyy = 1, RRYy = 2, RrYY = 2, RrYy = 4, Rryy = 2, rrYy = 2, rrYY = 1, rryy = 1
APPEARS IN
RELATED QUESTIONS
What is a dihybrid cross? How did Mendel perform this cross?
State Mendel’s law of Independent Assortment.
Complete the following sentence with appropriate word:
_______ is the ratio of dihybrid cross.
The physical expression of a gene is called ______.
Select the correct statement from the ones given below with respect to dihydrid cross
Which Mendelian idea is depicted by a cross in which the F1 generation resembles both the parents
In a test cross involving F1 dihybrid flies, more parental type offspring were produced than the recombination type offspring. This indicates
Explain the law of dominance in a monohybrid cross.
In a dihybrid cross, if you get 9:3:3:1 ratio it denotes that ______.
Two linked genes a and b show 20% recombination. The individuals of a dihybrid cross between ++ /++ × ab/ab shall show gametes ______.
Assertion: When the two genes in a dihybrid cross are situated on the same chromosome, the proportion of parental gene combinations is much higher than the nonparental type.
Reason: Higher parental gene combinations can be attributed to crossing over between two genes.
From the list given below, select the character which can be acquired but not inherited
Do genetic combination of mothers play a significant role in determining the sex of a new born?
Two pea plants - one with round yellow seeds (RRYY) and another with wrinkled green (rryy) seeds produce F1 progeny that have round, yellow (RrYy) seeds.
When F1 plants are self-pollinated, which new combination of characters is expected in F2 progeny? How many seeds with these new combinations of characters will be produced when a total 160 seeds are produced in F2 generation? Explain with reason.
Which of the following statement is not correct for two genes that show 50% recombination frequency?
When two hybrids rrTt and Rrtt are gassed, the phenotype ratio of offspring should be:
In the Mendelian dihybrid cross when heterozygous round yellow is self grossed, round green offsprings are represented by the genotype.
The ratio of 9 : 3 : 3 : 1 is due to:
Mendel's law of independent assortment is based on F2 ratio of: