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Question
Explain why the electron gain enthalpy of fluorine is less negative than that of chlorine.
Solution
In fluorine, the new electron to be added goes to 2p-subshell while in chlorine, the added electron goes to 3p-subshell. Since the 2p-subshell is relatively small as compared to 3p-subshell, the added electron in small 2p-subshell experiences strong interelectronic repulsions in comparison to that in 3p-subshell in \[\ce{Cl}\]. As a result, the incoming electron does not feel much attraction from the nucleus and therefore, the electron gain enthalpy of F is less negative than that of \[\ce{Cl}\].
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(ii) Chlorine has less negative electron gain enthalpy than fluorine.
(iii) Mercury and bromine are liquids at room temperature.
(iv) In any period, atomic radius of alkali metal is the highest.
Match the correct ionisation enthalpies and electron gain enthalpies of the following elements.
Elements | ∆H1 | ∆H2 | ∆egH | |
(i) Most reactive non-metal | A. | 419 | 3051 | – 48 |
(ii) Most reactive metal | B. | 1681 | 3374 | – 328 |
(iii) Least reactive element e | C. | 738 | 1451 | – 40 |
(iv) Metal forming binary halide | D. | 2372 | 5251 | + 48 |
Electronic configuration of some elements is given in Column I and their electron gain enthalpies are given in Column II. Match the electronic configuration with electron gain enthalpy.
Column (I) | Column (II) |
Electronic configuration | Electron gain enthalpy/kJ mol–1 |
(i) 1s2 2s2 sp6 | (A) – 53 |
(ii) 1s2 2s2 2p6 3s1 | (B) – 328 |
(iii) 1s2 2s2 2p5 | (C) – 141 |
(iv) 1s2 2s2 2p4 | (D) + 48 |
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Reason (R): Size of the atom increases on going down the group and the added electron would be farther from the nucleus.
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Reason: Fluorine has the highest negative electron gain enthalpy.
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