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Question
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm
Solution
Given:
Bases:
\[28 cm =\frac{28}{100}m = 0.28 m\]
And, 3 dm \[=\frac{3}{10}m = 0.3 m\]
Altitude = 25 cm\[ =\frac{25}{100}m = 0.25 m\]
Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the bases })\times( \text{ Altitude })\]
\[ = \frac{1}{2} \times (0 . 28 + 0 . 3) m \times (0 . 25) m\]
\[ {= 0.0725 m}^2 \]
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