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Question
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Solution
Given:
Sum of the parallel sides of a trapezium = 60 cm
\[ {\text{ Area of the trapezium }= 600 cm}^2 \]
\[\text{ Area of trapezium }=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Height })\]
On putting the values:
\[600 = \frac{1}{2} \times 60 \times (\text{ Height })\]
\[600 = 30 \times (\text{ Height })\]
\[\text{ Height }=\frac{600}{30}= 20 cm\]
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