Advertisements
Advertisements
Question
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200 cm ?
Solution
The triangle whose sides are
a = 150 cm
b = 120 cm
c = 200 cm
The area of a triangle =`sqrt(s(s-a)(s-b)(s-c)`
Here 1s = semi perimeter of triangle
`2s=a=b=c`
`s=(a+b+c)/2= (150+200+120)/2 =235 cm`
area of triangle =`sqrt(s(s-a)(s-b)(s-c)`
`=sqrt(235(235-150)(235-200)(235-120))`
`=sqrt(235(85)(35)(115))cm^2`
`=8966.56cm^2`
APPEARS IN
RELATED QUESTIONS
Find the area of the quadrilateral ABCD whose vertices are respectively A(1, 1), B(7, –3), C(12, 2) and D(7, 21).
Prove that the points (2, – 2), (–3, 8) and (–1, 4) are collinear
Show that the following sets of points are collinear.
(1, −1), (2, 1) and (4, 5)
Show that the points A(-5,6), B(3,0) and C(9,8) are the vertices of an isosceles right-angled triangle. Calculate its area.
Show that the points O(0,0), A`( 3,sqrt(3)) and B (3,-sqrt(3))` are the vertices of an equilateral triangle. Find the area of this triangle.
Find the value of y for which the points A(-3, 9), B(2,y) and C(4,-5) are collinear.
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
A field is in the shape of a right angled triangle whose base is 25 m and height 20 m. Find the cost of levelling the field at the rate of ₹ 45 per sq.m2
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of ∆ABC.