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Find ∣ ∣ → a − → B ∣ ∣ If | → a | = 2 , ∣ ∣ → B ∣ ∣ = 3 and → a ⋅ → B = 4 - Mathematics

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Question

Find \[\left| \vec{a} - \vec{b} \right|\] if  

\[\left| \vec{a} \right| = 2, \left| \vec{b} \right| = 3 \text{ and } \vec{a} \cdot \vec{b} = 4\]

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Notes

\[\text{ Given that }\]

\[\left| \vec{a} \right| = 2, \left| \vec{b} \right| = 3 \text{ and } \vec{a} . \vec{b} = 4........ \left( 1 \right)\]

\[\text{ We know that }\]

\[ \left| \vec{a} - \vec{b} \right|^2 = \left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 - 2 \vec{a} . \vec{b} \]

\[ = 2^2 + 3^2 - 2 \left( 4 \right)............. \left[ \text{ Using } \left( 1 \right) \right]\]

\[ = 4 + 9 - 8\]

\[ = 5\]

\[ \therefore \left| \vec{a} - \vec{b} \right| = \sqrt{5}\]

  Is there an error in this question or solution?
Chapter 24: Scalar Or Dot Product - Exercise 24.1 [Page 31]

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RD Sharma Mathematics [English] Class 12
Chapter 24 Scalar Or Dot Product
Exercise 24.1 | Q 32.3 | Page 31

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