English

Find the coefficient of: (ii) x7 in the expansion of ( x − 1 x 2 ) 40 - Mathematics

Advertisements
Advertisements

Question

Find the coefficient of: 

(ii) x7 in the expansion of  \[\left( x - \frac{1}{x^2} \right)^{40}\]

 
 

Solution

(ii) Suppose x7 occurs at the (+ 1) th term in the given expression.

Then, we have:

\[T_{r + 1} = ^{40}{}{C}_r x^{40 - r} \left( \frac{- 1}{x^2} \right)^r \]
`= (-1)^r "^40C_r  x^(40-r-2r)`
\[\text{ For this term to contain } x^7 , \text{ we must have: } \]
\[40 - 3r = 7\]
\[ \Rightarrow 3r = 40 - 7 = 33\]
\[ \Rightarrow r = 11\]
\[ \therefore \text{ Coefficient of } x^7 = ( - 1 )^{11} \]` "^40C_11 = "^-40 C_11`

shaalaa.com
Introduction of Binomial Theorem
  Is there an error in this question or solution?
Chapter 18: Binomial Theorem - Exercise 18.2 [Page 37]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.2 | Q 9.2 | Page 37

RELATED QUESTIONS

Using binomial theorem, write down the expansions  :

(ii)  \[\left( 2x - 3y \right)^4\]

 


Using binomial theorem, write down the expansions  :

(iv)  \[\left( 1 - 3x \right)^7\]

 


Using binomial theorem, write down the expansions  :

(v) \[\left( ax - \frac{b}{x} \right)^6\]

 


Using binomial theorem, write down the expansions  :

(vi) \[\left( \frac{\sqrt{x}}{a} - \sqrt{\frac{a}{x}} \right)^6\]

 


Using binomial theorem, write down the expansions  :

(x)  \[\left( 1 - 2x + 3 x^2 \right)^3\]

 


Evaluate the 

(i)\[\left( \sqrt{x + 1} + \sqrt{x - 1} \right)^6 + \left( \sqrt{x + 1} - \sqrt{x - 1} \right)^6\]

 


Evaluate the

(iv)  \[\left( \sqrt{2} + 1 \right)^6 + \left( \sqrt{2} - 1 \right)^6\]

 


Evaluate the

(vi)  \[\left( 2 + \sqrt{3} \right)^7 + \left( 2 - \sqrt{3} \right)^7\]


Evaluate the

(vii) \[\left( \sqrt{3} + 1 \right)^5 - \left( \sqrt{3} - 1 \right)^5\]

 


Evaluate the

(ix) \[\left( \sqrt{3} + \sqrt{2} \right)^6 - \left( \sqrt{3} - \sqrt{2} \right)^6\]

 


Find  \[\left( a + b \right)^4 - \left( a - b \right)^4\] . Hence, evaluate \[\left( \sqrt{3} + \sqrt{2} \right)^4 - \left( \sqrt{3} - \sqrt{2} \right)^4\] .

 

Using binomial theorem evaluate :

(i) (96)3


Using binomial theorem evaluate  .

(ii) (102)5

 


Using binomial theorem evaluate .

(iii) (101)4

 


Using binomial theorem evaluate .

(iv) (98)5

 

Using binomial theorem, prove that \[2^{3n} - 7n - 1\] is divisible by 49, where \[n \in N\] .

 

Using binomial theorem, prove that  \[3^{2n + 2} - 8n - 9\]  is divisible by 64, \[n \in N\] .

 

Find the coefficient of: 

(iii)  \[x^{- 15}\]  in the expansion of  \[\left( 3 x^2 - \frac{a}{3 x^3} \right)^{10}\]

 

 


Find the coefficient of: 

(v)  \[x^m\]  in the expansion of  \[\left( x + \frac{1}{x} \right)^n\]

 

 


Find the coefficient of: 

(vi) x in the expansion of  \[\left( 1 - 2 x^3 + 3 x^5 \right) \left( 1 + \frac{1}{x} \right)^8\]

 

Does the expansion of \[\left( 2 x^2 - \frac{1}{x} \right)\] contain any term involving x9?

 
 

Write the sum of the coefficients in the expansion of \[\left( 1 - 3x + x^2 \right)^{111}\]

 

If the coefficient of x in \[\left( x^2 + \frac{\lambda}{x} \right)^5\]  is 270, then \[\lambda =\]

 
 

The coefficient of x4 in \[\left( \frac{x}{2} - \frac{3}{x^2} \right)^{10}\] is

 

If  \[T_2 / T_3\]  in the expansion of \[\left( a + b \right)^n \text{ and } T_3 / T_4\]  in the expansion of \[\left( a + b \right)^{n + 3}\]  are equal, then n =

 
 

The coefficient of x5 in the expansion of \[\left( 1 + x \right)^{21} + \left( 1 + x \right)^{22} + . . . + \left( 1 + x \right)^{30}\]

 

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×