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Question
Find the length of the hypotenuse of a square whose side is 16 cm.
Solution
ABCD is a square.
In right angled triangle Δ ABC,
`AC^2 = AB^2 + BC^2` ....(by Pythagoras theorem)
∴ `AC^2 = 16^2 + 16^2`
∴ `AC^2 = 256 + 256`
∴ `AC^2 = 512`
∴ `AC = 16sqrt2`
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