Advertisements
Advertisements
Question
Find the mean of each of the following frequency distributions
Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Frequency | 9 | 12 | 15 | 10 | 14 |
Solution
Let the assumed mean A = 25
Class interval | Mid value(x1) | d1 = x1 - 25 | `"u"_1=(x_1-25)/10` | f1 | f1u1 |
0 -10 | 5 | -20 | -2 | 9 | -18 |
10 - 20 | 15 | -10 | -1 | 12 | -12 |
20 - 30 | 25 | 0 | 0 | 15 | 0 |
30 - 40 | 35 | 10 | 1 | 10 | 10 |
40 - 50 | 45 | 20 | 2 | 14 | 28 |
N = 60 | `sumf_1"u"_1=8` |
We have
A = 25, h = 10
Mean `=A+hxx(sumf_1"u"_1)/N`
`=25+10xx8/60`
`=25+80/60`
= 25 + 1.333
= 26.333
APPEARS IN
RELATED QUESTIONS
Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.
Number of heartbeats per minute | 65 - 68 | 68 - 71 | 71 - 74 | 74 - 77 | 77 - 80 | 80 - 83 | 83 - 86 |
Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
The mean of the following frequency distribution is 62.8 and the sum of all the frequencies is 50. Compute the missing frequency f1 and f2.
Class | 0 - 20 | 20 - 40 | 40 - 60 | 60 - 80 | 80 - 100 | 100 - 120 |
Frequency | 5 | f1 | 10 | f2 | 7 | 8 |
The following distribution shows the daily pocket allowance given to the children of a multistorey building. The average pocket allowance is Rs 18.00. Find out the missing frequency.
Class interval | 11 - 13 | 13 - 15 | 15 - 17 | 17 - 19 | 19 - 21 | 21 - 23 | 23 - 25 |
Frequency | 7 | 6 | 9 | 13 | - | 5 | 4 |
Find the mean using direct method:
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Frequency | 7 | 5 | 6 | 12 | 8 | 2 |
Find the mean of the following frequency distribution, using the assumed-mean method:
Class | 100 – 120 | 120 – 140 | 140 – 160 | 160 – 180 | 180 – 200 |
Frequency | 10 | 20 | 30 | 15 | 5 |
The mean of 1, 3, 4, 5, 7, 4 is m. The numbers 3, 2, 2, 4, 3, 3, p have mean m − 1 and median q. Then, p + q =
A school has 4 sections of Chemistry in class X having 40, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student.
The average score of boys in an examination of a school is 71 and of girls is 73. The averages score of school in that examination is 71.8. Find the ratio of the number of boys between number of girls appeared in the examination.
di is the deviation of xi from assumed mean a. If mean = `x+(sumf_id_i)/(sumf_i),` then x is ______.
The daily income of a sample of 50 employees are tabulated as follows:
Income (in Rs) |
1 – 200 | 201 – 400 | 401 – 600 | 601 – 800 |
Number of employees |
14 | 15 | 14 | 7 |
Find the mean daily income of employees.