Advertisements
Advertisements
Question
Find the mode of the given data:
| Class Interval | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 |
| Frequency | 15 | 6 | 18 | 10 |
Solution
Here the maximum class frequency is 18, and the class corresponding to this frequency is 40-60.
So, the modal class is 40-60.
Now,
Modal class = 40-60, lower limit (/) of modal class – 40, class size (h)=20,
Frequency `(f_1)` of the modal class =18,
Frequency (𝑓0) of class preceding the modal class =6,
Frequency (𝑓2) of class succeeding the modal class = 10.
Now, let us substitute these values in the formula:
𝑀𝑜𝑑𝑒=𝑙+`((f_1−f_0)/(2f_1−f_0−f_2)) ×ℎ`
`= 40+((18−6)/(36−6−10)) ×20`
`= 40+(12/20) ×20`
= 40+12
= 52
Hence, the mode is 52.
APPEARS IN
RELATED QUESTIONS
The following table shows the ages of the patients admitted in a hospital during a year:
| Age (in years) | 5 − 15 | 15 − 25 | 25 − 35 | 35 − 45 | 45 − 55 | 55 − 65 |
| Number of patients | 6 | 11 | 21 | 23 | 14 | 5 |
Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data.
| Number of cars | 0 − 10 | 10 − 20 | 20 − 30 | 30 − 40 | 40 − 50 | 50 − 60 | 60 − 70 | 70 − 80 |
| Frequency | 7 | 14 | 13 | 12 | 20 | 11 | 15 | 8 |
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
| Monthly consumption (in units) | Number of consumers |
| 65 - 85 | 4 |
| 85 - 105 | 5 |
| 105 - 125 | 13 |
| 125 - 145 | 20 |
| 145 - 165 | 14 |
| 165 - 185 | 8 |
| 185 - 205 | 4 |
The frequency distribution for agriculture holdings in a village is given below:
| Area of land (in hectares) | 1 – 3 | 3 – 5 | 5 – 7 | 7 – 9 | 9 – 11 | 11 – 13 |
| Number of families | 20 | 45 | 80 | 55 | 40 | 12 |
Find the modal agriculture holding per family.
Find out the mode from the following data:
| Wages (in ₹) | No. of persons |
| 125 | 3 |
| 175 | 8 |
| 225 | 21 |
| 275 | 6 |
| 325 | 4 |
| 375 | 2 |
A study of the yield of 150 tomato plants, resulted in the record:
| Tomatoes per Plant | 1 - 5 | 6 - 10 | 11 - 15 | 16 - 20 | 21 - 25 |
| Number of Plants | 20 | 50 | 46 | 22 | 12 |
What is the frequency of the class preceding the modal class?
Find the mode of the following distribution:
| Weight (in kgs) | 25 − 34 | 35 − 44 | 45 − 54 | 55 − 64 | 65 − 74 | 75 − 84 |
| Number of students | 4 | 8 | 10 | 14 | 8 | 6 |
Find the mode of the following data.
| Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
| Frequency | 7 | 13 | 14 | 5 | 11 |
For the following distribution:
| Class | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 |
| Frequency | 10 | 15 | 12 | 20 | 9 |
the upper limit of the modal class is:
The following frequency distribution table shows the classification of the number of vehicles and the volume of petrol filled in them. To find the mode of the volume of petrol filled, complete the following activity:
| Class (Petrol filled in Liters) |
Frequency (Number of Vehicles) |
| 0.5 - 3.5 | 33 |
| 3.5 - 6.5 | 40 |
| 6.5 - 9.5 | 27 |
| 9.5 - 12.5 | 18 |
| 12.5 - 15.5 | 12 |
Activity:
From the given table,
Modal class = `square`
∴ Mode = `square + [(f_1 - f_0)/(2f_1 -f_0 - square)] xx h`
∴ Mode = `3.5 + [(40 - 33)/(2(40) - 33 - 27)] xx square`
∴ Mode = `3.5 +[7/(80 - 60)] xx 3`
∴ Mode = `square`
∴ The mode of the volume of petrol filled is `square`.
