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The frequency distribution for agriculture holdings in a village is given below: Area of land (in hectares) 1 – 3 3 – 5 5 – 7 7 – 9 9 – 11 11 – 13 Number of families 20 45 80 55 40 12 - Mathematics

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Question

The frequency distribution for agriculture holdings in a village is given below:

Area of land (in hectares)  1 – 3  3 – 5   5 – 7 7 – 9 9 – 11 11 – 13
Number of families  20 45 80 55 40 12

Find the modal agriculture holding per family.

Sum

Solution

The maximum class frequency is 80. The class corresponding to this frequency is 5 – 7.

So, the modal class is 5 – 7.

l (the lower limit of modal class) = 5

f1 (frequency of the modal class) = 80

f(frequency of the class preceding the modal class) = 45

f(frequency of the class succeeding the modal class) = 55

h (class size) = 2

⇒ Mode = `l + ((f_1 - f_0)/(2f_1 - f_0 - f_2)) xx h`

= `5 + ((80 - 45)/(2 xx 80 - 45 - 55)) xx 2`

= `5 + (35/(160 - 100)) xx 2`

= `5 + (35 xx 2)/60`

= 5 + 1.167

= 6.167

Hence, the modal agricultural holdings of the village is 6.167 hectares.

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Chapter 15: Statistics - Exercise 15.5 [Page 47]

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