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Question
The following are the ages of 300 patients getting medical treatment in a hospital on a particular day:
Age (in years) | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 -70 |
Number of patients | 6 | 42 | 55 | 70 | 53 | 20 |
Form a ‘less than type’ cumulative frequency distribution.
Solution
A ‘less than type’ cumulative frequency distribution table is given below:
Age (in years) | Cumulative frequency (𝑐𝑓) |
Less than 20 | 60 |
Less than 30 | 102 |
Less than 40 | 157 |
Less than 50 | 227 |
Less than 60 | 280 |
Less than 70 | 300 |
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Less than 150 |
Less than 200 |
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Consider the following frequency distributions
Class | 65 - 85 | 85 - 105 | 105 - 125 | 125 - 145 | 145 - 165 | 165 - 185 | 185-205 |
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Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
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For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are.
Number of days | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 | 25 - 30 | 30 - 35 | 35 - 40 | TOTAL |
Total Number of students | 15 | 16 | x | 8 | y | 8 | 6 | 4 | 70 |
Consider the following distribution:
Marks obtained | Number of students |
More than or equal to 0 | 63 |
More than or equal to 10 | 58 |
More than or equal to 20 | 55 |
More than or equal to 30 | 51 |
More than or equal to 40 | 48 |
More than or equal to 50 | 42 |
The frequency of the class 30 – 40 is:
Look at the following table below.
Class interval | Classmark |
0 - 5 | A |
5 - 10 | B |
10 - 15 | 12.5 |
15 - 20 | 17.5 |
The value of A and B respectively are?
Form the frequency distribution table from the following data:
Marks (out of 90) | Number of candidates |
More than or equal to 80 | 4 |
More than or equal to 70 | 6 |
More than or equal to 60 | 11 |
More than or equal to 50 | 17 |
More than or equal to 40 | 23 |
More than or equal to 30 | 27 |
More than or equal to 20 | 30 |
More than or equal to 10 | 32 |
More than or equal to 0 | 34 |