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Question
The following table gives the production yield per hectare of wheat of 100 farms of a village.
| Production Yield (kg/ha) | 50 –55 | 55 –60 | 60 –65 | 65- 70 | 70 – 75 | 75 80 |
| Number of farms | 2 | 8 | 12 | 24 | 238 | 16 |
Change the distribution to a ‘more than type’ distribution and draw its ogive. Using ogive, find the median of the given data.
Solution
The frequency distribution table of more than type is as follows:
| Production yield (kg/ha) (lower class limits) | Cumulative frequency (cf) |
| More than 50 | 2 + 98 = 100 |
| More than 55 | 8 + 90 = 98 |
| More than 60 | 12 + 78 = 90 |
| More than 65 | 24 + 54 = 78 |
| More than 70 | 38 + 16 = 54 |
| More than 75 | 16 |
Taking the lower class limits on x-axis and their respective cumulative on y-axis, its ogive can be drawn as follows
Here, N = 100 ⇒ `N/2 = 50.`
Mark the point A whose ordinate is 50 and its x-coordinate is 70.5.
Thus, median of the data is 70.5.
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