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The Following Are the Ages of 300 Patients Getting Medical Treatment in a Hospital on a Particular Day: Form a ‘Less than Type’ Cumulative Frequency Distribution. - Mathematics

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प्रश्न

The following are the ages of 300 patients getting medical treatment in a hospital on a particular day:

Age (in years) 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60 60 -70
Number of patients 6 42 55 70 53 20

Form a ‘less than type’ cumulative frequency distribution.

उत्तर

A ‘less than type’ cumulative frequency distribution table is given below:

Age (in years) Cumulative frequency (𝑐𝑓)
Less than 20 60
Less than 30 102
Less than 40 157
Less than 50 227
Less than 60 280
Less than 70 300
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अध्याय 9: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - Exercises 6

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 9 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
Exercises 6 | Q 16

संबंधित प्रश्न

Find the median of the following data by making a ‘less than ogive’.

Marks 0 - 10 10-20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80-90 90-100
Number of Students 5 3 4 3 3 4 7 9 7 8

 


Draw a ‘more than’ ogive for the data given below which gives the marks of 100 students.

Marks 0 – 10 10 – 20 20 – 30 30 - 40 40 – 50 50 – 60 60 – 70 70 – 80
No of Students 4 6 10 10 25 22 18 5

 


The heights of 50 girls of Class X of a school are recorded as follows:

Height (in cm) 135 - 140 140 – 145 145 – 150 150 – 155 155 – 160 160 – 165
No of Students 5 8 9 12 14 2

Draw a ‘more than type’ ogive for the above data.


From the following frequency, prepare the ‘more than’ ogive.

Score Number of candidates
400 – 450 20
450 – 500 35
500 – 550 40
550 – 600 32
600 – 650 24
650 – 700 27
700 – 750 18
750 – 800 34
Total 230

Also, find the median.


 The following is the cumulative frequency distribution ( of less than type ) of 1000 persons each of age 20 years and above . Determine the mean age .

Age below (in years): 30 40 50 60 70 80
Number of persons : 100 220 350 750 950 1000

Consider the following frequency distribution :

Class: 0-5      6-11   12-17  18-23   24-29
Frequency:   13 10 15 8 11

The upper limit of the median class is 


The arithmetic mean of the following frequency distribution is 53. Find the value of k.

Class 0-20 20-40 40-60 60-80 80-100
Frequency 12 15 32 k 13

If the median of the following frequency distribution is 32.5. Find the values of f1 and f2.

Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Total
Frequency f1 5 9 12 f2 3 2 40

Look at the following table below.

Class interval Classmark
0 - 5 A
5 - 10 B
10 - 15 12.5
15 - 20 17.5

The value of A and B respectively are?


The following table shows the cumulative frequency distribution of marks of 800 students in an examination:

Marks Number of students
Below 10 10
Below 20 50
Below 30 130
Below 40 270
Below 50 440
Below 60 570
Below 70 670
Below 80 740
Below 90 780
Below 100 800

Construct a frequency distribution table for the data above.


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