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Question
Find the 10th term from the end of the A.P. 4, 9, 14, .........., 254.
Solution
The given A.P. is 4, 9, 14, .........., 254
First term = 4
Common difference = 9 – 4 = 5
Last term = l = 254
For the reverse A.P. first term = 254 and common difference = –5
Thus, 10th term from the end of a given A.P.
= 10th term from the end of a given A.P.
= 254 + (10 – 1) × (–5)
= 254 – 45
= 209
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