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Question
Find the amount of water displaced by a solid spherical ball of diameter 0.21 m.
`["Assume "pi=22/7]`
Solution
Radius (r) of ball = `(0.21/2)m` = 0.105 m
Volume of ball = `4/3pir^3`
= `[4/3xx22/7xx(0.105)^3]m^3`
= 0.004851 m3
Thus, the amount of water displaced is 0.004851 m3.
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