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Question
Find the area and the perimeter of a square with diagonal 24 cm. [Take √2 = 1.41 ]
Solution
Diagonal of a square = 24 cm
Now, diagonal of a square = side of a square x `sqrt2`
⇒ 24 = side of a Square x `sqrt2`
⇒ Side of a square = `24/[sqrt2] = [12 xx sqrt2 xx sqrt2 ]/[sqrt2 ] = 12sqrt2`
∴ Area of a square = ( Side )2 = ( 12√2)2 = 288 cm2
And, perimeter of a square =
= 4 x Side
= 4 x 12`sqrt2`
= 48 x 1. 41
= 67. 68 cm.
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