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Find the assignments of salesman to various district which will yield maximum profit Salesman District 1 2 3 4 A 16 10 12 11 B 12 13 15 15 C 15 15 11 14 D 13 14 14 15 - Mathematics and Statistics

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Question

Find the assignments of salesman to various district which will yield maximum profit

Salesman District
1 2 3 4
A 16 10 12 11
B 12 13 15 15
C 15 15 11 14
D 13 14 14 15
Chart
Sum

Solution

Step 1: 

Since it is a maximization problem, subtract each of the elements in the table from the largest element, i.e., 16

Salesman District
1 2 3 4
A 0 6 4 5
B 4 3 1 1
C 1 1 5 2
D 3 2 2 1

Step 2: Row minimum

Subtract the smallest element in each row from every element in its row.

The matrix obtained is given below:

Salesman District
1 2 3 4
A 0 6 4 5
B 3 2 0 0
C 0 0 4 1
D 2 1 1 0

Step 3: Column minimum

Here, each column contains element zero.

∴ Matrix obtained by column minimum is same as above matrix.

Step 4:

Draw minimum number of vertical and horizontal lines to cover all zeros.

First cover all rows and columns which have maximum number of zeros.

Salesman District
1 2 3 4
A 0 6 4 5
B 3 2 0 0
C 0 0 4 1
D 2 1 1 0

Step 5: 

From step 4, minimum number of lines covering all the zeros are 4, which is equal to order of the matrix, i.e., 4.

∴ Select a row with exactly one zero, enclose that zero in () and cross out all zeros in its respective column.

Similarly, examine each row and column and mark the assignment ().

∴ The matrix obtained is as follows:

Salesman District
1 2 3 4
A 0 6 4 5
B 3 2 0 0
C 0 0 4 1
D 2 1 1 0

Step 6:

The matrix obtained in step 5 contains exactly one assignment for each row and column.

Optimal assignment schedule is as follows:

Salesman District Profit (in ₹)
A 1 16
B 3 15
C 2 15
D 4 15

∴ The maximum profit

= 16 + 15 + 15 + 15

= ₹ 61

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Special Cases of Assignment Problem
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Chapter 2.7: Assignment Problem and Sequencing - Q.4

RELATED QUESTIONS

Four new machines M1, M2, M3 and M4 are to be installed in a machine shop. There are five vacant places A, B, C, D and E available. Because of limited space, machine M2 cannot be placed at C and M3 cannot be placed at A. The cost matrix is given below.

Machines Places
  A B C D E
M1 4 6 10 5 6
M2 7 4 5 4
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M4 9 3 7 2 3

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In maximization type, all the elements in the matrix are subtracted from the _______ element in the matrix.


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P Q R S
I 34 36 33 35
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V 35 36 35 33

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The cost matrix of an unbalanced assignment problem is not a ______


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