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Question
Find the derivatives of the following:
`x^2/"a"^2 + y^2/"b"^2` = 1
Solution
`x^2/"a"^2 + y^2/"b"^2` = 1
`(2x)/"a"^2 + (2y)/"b"^2 ("d"y)/("d"x)` = 0
`(2y)/"b"^2 ("d"y)/("d"x) = - (2x)/"a"^2`
`("d"y)/("d"x) = - (2x)/"a"^2 xx "b"^2/(2y)`
`("d"y)/("d"x) = - "b"^2/"a"^2 x/y`
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