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Question
Find the equation of a straight line which cuts an intercept of 5 units on Y-axis and is parallel to the line joining the points (3, – 2) and (1, 4).
Solution
Let m be the slope of the required line and since the required line is parallel to the line joining the points (3, - 2) and (1, 4).
Hence, slope of the line
m = `(4 + 2)/(1 - 3)`
= `(6)/(-2)`
= -3.
Also, Y-intercept c = 5 units
So, equation of the required line be
y = mx + c
⇒ y = -3x + 5
⇒ 3x + y - 5 = 0.
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