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Question
Find the equation of the circle having (4, 7) and (-2, 5) as the extremities of a diameter.
Solution
The equation of the circle when entremities (x1, y1) and (x2, y2) are given is (x – x1) (x – x2) + (y – y1) (y – y2) = 0
⇒ (x – 4) (x + 2) + (y – 7) (y – 5) = 0
⇒ x2 – 2x – 8 + y2 – 12y + 35 = 0
⇒ x2 + y2 – 2x – 12y + 27 = 0
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