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Question
Find centre and radius of the following circles
x2 + y2 – x + 2y – 3 = 0
Solution
2g = – 1
2f = 2
c = – 3
g = `(-1)/2` f = 1
Centre (– g, – f) = `(1/2, -1)`
Radius = `sqrt(g^2 + f^2 - "c")`
= `sqrt(1/4 + 1 + 3)`
`sqrt(1 + 4 + 12/4)`
`sqrt(17/4) = sqrt(17)/2`
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