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Find the mean, variance and standard deviation using short-cut method. Height in cms 70 - 75 75 - 80 80 - 85 85 - 90 90 - 95 95 - 100 100 - 105 105 - 110 110 - 115 No. of children 3 4 7 7 15 9 6 6 3 - Mathematics

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Question

Find the mean, variance and standard deviation using short-cut method.

Height in cms 70 - 75 75 - 80 80 - 85 85 - 90 90 - 95 95 - 100 100 - 105 105 - 110 110 - 115
No. of children 3 4 7 7 15 9 6 6 3
Sum

Solution

Class Interval Mid-point Frequency yi fiyi yi2 fi2
70 - 75 72.5 3 −4 −12 16 48
75 - 80 77.5 4 −3 −12 9 36
80 - 85 82.5 7 −2 −14 4 28
85 - 90 87.5 7 −1 7 1 7
90 - 50 92.5 15 0 0 0 0
95 - 100 97.5 9 1 9 1 9
100 - 105 102.5 6 2 12 4 24
105 - 110  107.5 6 3 18 9 54
110 - 115 112.5 3 4 12 16 48
Sum - 60 - 6 - 254

Mean, `overlinex = A + ((sumf_iy_i))/N xx h`

= `9.25 + 6/60 xx 5`

= 92.5 + 0.5 

= 93

Variance, σ2 = `h^2/N^2[Nsum f_iy_i^2 - (sumf_iy_i)^2]`

= `25/3600 [60 xx 254 - 36]`

= `12/144 [5 xx 254 - 3]`

= `1/12 [1270 - 3]`

= `1267/12`

= 105.58

Standard deviation, σ = `sqrt(105.58)`

= 10.28

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Chapter 15: Statistics - Exercise 15.2 [Page 372]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 15 Statistics
Exercise 15.2 | Q 9 | Page 372

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