Advertisements
Advertisements
Question
Find the radius of the spherical tank whose volume is `(32pi)/3` units
Solution
Let r be the radius of the spherical tank.
Given volume of the spherical tank = `(32pi)/3`
`4/3pir^3 = (32pi)/3`
4r3 = 32
r3 = `32/4` = 8
r3 = 23
r = 2
∴ Radius of the spherical tank r = 2 units.
APPEARS IN
RELATED QUESTIONS
Simplify: `(125)^(2/3)`
Simplify: `16^((-3)/4)`
Simplify: `(- 1000)^((-2)/3)`
Simplify: `(3^-6)^(1/3)`
Simplify: `(27^((-2)/3))/(27^((-1)/3))`
Evaluate `[((256)^(-1/2))^((-1)/4)]^3`
If `(x^(1/2) + x^(- 1/2))^2 = 9/2` then find the value of `(x^(1/2) - x^(-1/2))` for x >1
Simplify and hence find the value of n:
`(3^(2"n")*9^2*3^(-"n"))/(3^(3"n"))` = 27
. Simplify by rationalising the denominator `(7 + sqrt(6))/(3 - sqrt(2))`
Simplify `1/(3 - sqrt(8)) - 1/(sqrt(8) - sqrt(7)) + 1/(sqrt(7) - sqrt(6)) - 1/(sqrt(6) - sqrt(5)) + 1/(sqrt(5) - 2)`
If x = `sqrt(2) + sqrt(3)` find `(x^2 + 1)/(x^2 - 2)`
