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Tamil Nadu Board of Secondary EducationHSC Commerce Class 12

Find the rank of the matrix A = (452232164480) - Business Mathematics and Statistics

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Question

Find the rank of the matrix

A = `((4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0))`

Chart
Sum

Solution

A = `[(4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0)]`

The order of A is 3 × 4

∴ p(A) < 3

Let us transform the matrix A to an echelon form

Martix Elementary
Transformation
A = `[(4, 5, 2, 2),(3, 2, 1, 6),(4, 4, 8, 0)]`  
`∼ [(3, 2, 1, 6),(4, 5, 2, 2),(4, 4, 8, 0)]` `{:"R"_1 ↔ "R"_2:}`
`∼ [(3, 2, 1, 6),(4, 5, 2, 2),(0, -1, 6, -2)]` `{:"R"_3 ↔ "R"_2:}`
`∼ [(3, 2, 1, 6),(1, 3, 1, -4),(0, -1, 6, -2)]` `{:"R"_2 -> "R"_2 - "R"_1:}`
`∼ [(1, 3, 1, -4),(3, 2, 1, 6),(0, -1, 6, -2)]` `{:"R"_1 ↔ "R"_2:}`
`∼ [(1, 3, 1, -4),(0, -7, -2, 18),(0, -1, 6, -2)]` `{:"R"_2 -> "R"_3 - 3"R"_1:}`
`∼ [(1, 3, 1, -4),(0, -1, 6, -2),(0, -7, -2, 18)]` `{:"R"_2 ↔ "R"_3:}`
`∼ [(1, 3, 1, -4),(0, -1, 6, -2),(0, 0, -44, 32)]` `{:"R"_3 -> "R"_3 - 3"R"_1:}`

The last equivalent matrix is in the echelon form.

Number of non-zero rows = 3

∴ p(A) = 3

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Rank of a Matrix
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Chapter 1: Applications of Matrices and Determinants - Miscellaneous problems [Page 22]

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Samacheer Kalvi Business Mathematics and Statistics [English] Class 12 TN Board
Chapter 1 Applications of Matrices and Determinants
Miscellaneous problems | Q 3 | Page 22
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