Advertisements
Advertisements
Question
Find the three numbers in AP whose sum is 15 and product is 80.
Solution
Let the required numbers be (a -d ),a and (a + d).
Then (a-d) +a + (a+d)=15
⇒ 3a =15
⇒a=5
Also, (a-d) . a . (a+d) = 80
⇒` a(a^2 - d^2 ) = 80`
⇒`5 (25 - d^2 ) = 80 `
⇒` d^2 = 25-16=9 `
⇒ `d =+- 3`
Thus a= 5 and `d = +- 3`
Hence, the required numbers are (2,5 and 8) or (8,5 and 2).
APPEARS IN
RELATED QUESTIONS
In an AP given a3 = 15, S10 = 125, find d and a10.
Show that a1, a2,..., an... form an AP where an is defined as below:
an = 3 + 4n
Also, find the sum of the first 15 terms.
Find the sum of the first 25 terms of an A.P. whose nth term is given by an = 2 − 3n.
The first and the last terms of an A.P. are 34 and 700 respectively. If the common difference is 18, how many terms are there and what is their sum?
Find the A.P. whose fourth term is 9 and the sum of its sixth term and thirteenth term is 40.
If the sum of first p term of an A.P. is ap2 + bp, find its common difference.
If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 terms is
The sum of n terms of an A.P. is 3n2 + 5n, then 164 is its
Find the sum of numbers between 1 to 140, divisible by 4
An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three is 429. Find the AP.