Advertisements
Advertisements
Question
Find two consecutive even numbers, whose sum is 38.
Solution
Let the two consecutive even numbers be 2n and 2n + 1.
Then As per the question,
2n + (2n + 2) = 38
⇒ 4n = 36 or n = 9
Thus, numbers are 2n = 18 and 2n + 1 = 20.
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
9y -7 = 20
4x – 5x + 2x = 28 + 3x
Solve: `"x"/2 + "x"/5 = 14`
Solve: `"2p"/3 - "p"/5 = 35`
Solve: `("x" - 4)/7 = "x + 3"/7 + "x + 4"/5`
The numerator of a fraction is four less than its denominator. If 1 is added to both, is numerator and denominator, the fraction becomes `1/2` Find the fraction.
Solve the following equations for the unknown: `(2x + 3)/(x + 7) = (5)/(8), x ≠ -7`
Solve the following equations for the unknown: `2(1)/(5) - (x - 2)/(3) = (x - 1)/(3)`
For two consecutive odd natural numbers, the square of bigger number exceeds the square of smaller number by 72. Find the two numbers.
Shweta's age is six times that of Jayeeta's age. 15 years hence Shweta will be three times as old as Jayeeta; find their ages.
