Advertisements
Advertisements
Question
Find the value of a, if x + 2 is a factor of 4x4 + 2x3 − 3x2 + 8x + 5a.
Solution
Let 4x4 + 2x3 − 3x2 + 8x + 5a be the polynomial.
By the factor theorem,
(x+2)is a factor of f(x) if f(−2) = 0.
Therefore,
`f(2) = 4(-2)^4 + 2(-2)^3 - 3(-2)^2 + 8(-2) + 5a = 0`
`64 - 16 - 12 - 16 + 5a = 0`
`5a = -20`
`a = -4`
Hence, `a = -4`
APPEARS IN
RELATED QUESTIONS
f(x) = x3 − 6x2 + 2x − 4, g(x) = 1 − 2x
If the polynomials ax3 + 3x2 − 13 and 2x3 − 5x + a, when divided by (x − 2) leave the same remainder, find the value of a.
In each of the following, use factor theorem to find whether polynomial g(x) is a factor of polynomial f(x) or, not: (1−7)
f(x) = x3 − 6x2 + 11x − 6; g(x) = x − 3
In the following two polynomials, find the value of a, if x − a is factor (x5 − a2x3 + 2x + a + 1).
Find the values of a and b so that (x + 1) and (x − 1) are factors of x4 + ax3 − 3x2 + 2x + b.
If x3 + ax2 − bx+ 10 is divisible by x2 − 3x + 2, find the values of a and b.
If both x + 1 and x − 1 are factors of ax3 + x2 − 2x + b, find the values of a and b.
What must be added to 3x3 + x2 − 22x + 9 so that the result is exactly divisible by 3x2 + 7x − 6?
x3 + 2x2 − x − 2
Let f(x) be a polynomial such that \[f\left( - \frac{1}{2} \right)\] = 0, then a factor of f(x) is