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Question
Find the values of x for which the distance between the point P(2, −3), and Q (x, 5) is 10.
Solution
It is given that distance between P (2,−3) and Q (x , 5) is 10.
In general, the distance between A`(x_1 , y_1) " and B " (x_2 , y_2 )` is given by,
`AB^2 = (x_2 - x_1 )^2 + (y_2 - y_1)^2`
So,
`10^2 = ( x - 2)^2 + ( 5 +3)^2`
On further simplification,
`(x - 2)^2 = 36`
` x = 2 +- 6`
= 8 , - 4
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