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Question
Find x, if
Solution
\[\left( \frac{8}{3} \right)^{2x + 1} \times \left( \frac{8}{3} \right)^5 = \left( \frac{8}{3} \right)^{x + 2}\]
\[\left( \frac{8}{3} \right)^{2x + 1} = \left( \frac{8}{3} \right)^{x + 2}\]
2x + 6 = x+2
x = -4
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