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Question
Following are APs or not? If they form an A.P. find the common difference d and write three more terms:
`-1/2, -1/2, -1/2, -1/2` ....
Solution
`-1/2, -1/2, -1/2, -1/2 ....`
Here,
a2 - a1 = `(-1/2) - (-1/2) = 0`
a3 - a2 = `(-1/2) - (-1/2) = 0`
a4 - a3 = `(-1/2) - (-1/2) = 0`
⇒ an+1 - an is same every time.
Therefore, d = 0 and the given numbers are in A.P.
Three more terms are
a5 = `(-1/2) - 0 = -1/2`
a6 = `(-1/2) - 0 = -1/2`
a7 = `(-1/2) - 0 = -1/2`
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