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Question
For an event E, if `P(E) + P(barE)` = q, then the value of q2 − 4 is ______.
Options
−3
3
5
−5
Solution
For an event E, if `P(E) + P(barE)` = q, then the value of q2 − 4 is −3.
Explanation:
In probability theory, the sum of the probability of an event (E) and its complement `p(barE)` is always equal to 1. This is because these two events are exhaustive (cover all possibilities) and mutually exclusive (can't happen together).
So, we know:
`P(E) + P(barE)` = 1
We are given that `P(E) + P(barE)` = q, which must also be equal to 1.
Therefore, q = 1.
Now we can find q2 − 4:
q2 − 4
= 12 − 4
= 1 − 4
= −3
So the value of q2 − 4 is −3.
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