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Question
For the following bond cleavages, use curved-arrows to show the electron flow and classify as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
Solution
The bond cleavage using curved-arrows to show the electron flow of the given reaction can be represented as
It is an example of heterolytic cleavage as the bond breaks in such a manner that the shared pair of electrons remains with the bromine ion. The reaction intermediate formed is a carbocation.
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For the following bond cleavages, use curved arrows to show the electron flow and classify homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
\[\ce{CH3O - OCH3 -> CH3\overset\bullet{\text{O}} + \overset\bullet{\text{O}}CH3}\]
For the following bond cleavages, use curved-arrows to show the electron flow and classify as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
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What is the correct order of decreasing stability of the following cations.
| I. | \[\ce{CH3 - \overset{⊕}{C}H - CH3}\] |
| II. | \[\ce{CH3 - \overset{⊕}{C}H - OCH3}\] |
| III. | \[\ce{CH3 - \overset{⊕}{C}H - CH2 - OCH3}\] |
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| (ii) Carbocation | (b) Pyramidal |
| (iii) Carbanion | (c) Linear |
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 |
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| (I) | (II) | (III) | (IV) |
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\[\ce{CH2 = \overset{⊕}{C}H}\] | \[\ce{CH3 - \overset{⊕}{C}H2}\] | \[\ce{HC ≡ \overset{⊕}{C}}\] |
| A | B | C | D |
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