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Question
For the following polynomial, find p(1), p(0) and p(-2).
p(x) = x4 − 2x2 − x
Solution
p(x) = x4 − 2x2 − x
∴ p(1) = (1)4 − 2 × (1)2 − 1
= 1 − 2 − 1
= −2
∴ p(0) = (0)4 − 2 × (0)2 − 0
= 0 − 0 − 0
= 0
∴ p(−2) = (−2)4 − 2 × (−2)2 − (−2)
= 16 − 2 × 4 + 2
= 16 − 8 + 2
= 10
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