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For the function f(x) = x+1x, x ∈ [1, 3], the value of c for mean value theorem is ______. - Mathematics

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Question

For the function f(x) = `x + 1/x`, x ∈ [1, 3], the value of c for mean value theorem is ______.

Options

  • 1

  • `sqrt(3)`

  • 2

  • None of these

MCQ
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Solution

For the function f(x) = `x + 1/x`, x ∈ [1, 3], the value of c for mean value theorem is `sqrt(3)`.

Explanation:

Given that: f(x) = `x + 1/x`, x ∈ [1, 3]

We know that if f(x) =  `x + 1/x`, x ∈ [1, 3] satisfies all the conditions of mean value theorem then

f'(c) = `("f"("b") - "f"("a"))/("b" - "a")` where a = 1 and b = 3

⇒ `1 - 1/"c"^2 = ((3 + 1/3) - (1 + 1/1))/(3 - 1)`

⇒ `1 - 1/"c"^2 = (10/3 - 2)/2`

⇒ `1 - 1/"c"^2 = 4/6 = 2/3`

⇒ `- 1/"c"^2 = 2/3 - 1`

⇒ `- 1/"c"^2 = -1/3`

⇒ `1/"c"^2 = 1/3`

⇒ c = `+- sqrt(3)`.

Here c = `sqrt(3) ∈ (1, 3)`.

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Chapter 5: Continuity And Differentiability - Exercise [Page 116]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 5 Continuity And Differentiability
Exercise | Q 96 | Page 116

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