English

How Many Cubic Metres of Earth Must Be Dugout to Sink a Well 21 M Deep and 6 M Diameter? Find the Cost of Plastering the Inner Surface of the Well at Rs 9.50 per M2 - Mathematics

Advertisements
Advertisements

Question

How many cubic metres of earth must be dugout to sink a well 21 m deep and 6 m diameter? Find the cost of plastering the inner surface of the well at Rs 9.50 per m2

Sum

Solution

Given data is as follows:

 h = 21 m

Diameter = 6 m

Plastering rate = Rs.9.50/m2

We have to find the volume and the cost of plastering the inner surface of this well.

Given is the diameter, which is 6 m. Therefore,

`r=6/2`

r = 3

We know that,

Volume =`pir^2h`

=`22/7 xx 3xx3xx21`

Volume = 594 m3

We know that,

Curved Surface Area = `2pirh`

= `2 xx 22/7 xx 3 xx 21`

Curved Surface Area =396 m2

Total cost of plastering = ( Curved Surface Area ) × (Plastering rate )

                                    =396 × 9.50

                                    = 3762

Therefore, the volume of this well is 594 m3 and cost of plastering its inner surface is Rs.3762.

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Surface Areas and Volume of a Circular Cylinder - Exercise 19.2 [Page 21]

APPEARS IN

RD Sharma Mathematics [English] Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.2 | Q 17 | Page 21

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find

(i) Its inner curved surface area,

(ii) The cost of plastering this curved surface at the rate of Rs 40 per m2.

`["Assume "pi=22/7]`

 


In the given figure, you see the frame of a lampshade. It is to be covered with a decorative cloth. The frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. Find how much cloth is required for covering the lampshade.

`["Assume "pi=22/7]`

 


The diameter of roller 1.5 m long is 84 cm. If it takes 100 revolutions to level a playground, find the cost of levelling this ground at the rate of 50 paise per square metre. 


The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the area of the curved surface. Find the volume of the cylinder.


A well with 10 m inside diameter is dug 8.4 m deep. Earth taken out of it is spread all around it to a width of 7.5 m to form an embankment. Find the height of the embankment.


A rectangular sheet of paper 30 cm × 18 cm can be transformed into the curved surfaced of a right circular cylinder in two ways i.e., either by rolling the paper along its length or by rolling it along its breadth. Find the ratio of the volumes of the two cylinders thus formed.


A well with 14 m diameter is dug 8 m deep. The earth taken out of it has been evenly spread all around it to a width of 21 m to form an embankment. Find the height of the embankment.


Vertical cross-section of a right circular cylinder is always a


A right circular cylindrical tunnel of diameter 2 m and length 40 m is to be constructed from a sheet of iron. The area of the iron sheet required in m2, is


The inner diameter of a well is 4.20 metre and its depth is 10 metre. Find the inner surface area of the well. Find the cost of plastering it from inside at the rate Rs.52 per sq.m.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×