Advertisements
Advertisements
Question
If a = 1 + i, then a2 equals
Options
1 − i
2i
(1 + i) (1 − i)
i − 1.
Solution
2i
a = 1 + i
On squaring both the sides, we get,
a2 = (1 + i)2
\[\Rightarrow\] a2 = 1 + i2 + 2i
\[\Rightarrow\] a2 = 1 \[-\] 1 + 2i ( ∵ i2 = \[-\] 1)
\[\Rightarrow\] a2 = 2i
APPEARS IN
RELATED QUESTIONS
Find the square root of the following complex number:
−5 + 12i
Find the square root of the following complex number:
−7 − 24i
Find the square root of the following complex number:
1 − i
Find the square root of the following complex number:
−8 − 6i
Find the square root of the following complex number:
8 −15i
Find the square root of the following complex number:
\[- 11 - 60\sqrt{- 1}\]
Find the square root of the following complex number:
\[1 + 4\sqrt{- 3}\]
Find the square root of the following complex number:
4i
Find the square root of the following complex number:
−i
Write the values of the square root of i.
Write the values of the square root of −i.
If x + iy =\[\sqrt{\frac{a + ib}{c + id}}\] then write the value of (x2 + y2)2.
If\[\sqrt{a + ib} = x + iy,\] then possible value of \[\sqrt{a - ib}\] is