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Maharashtra State BoardSSC (English Medium) 9th Standard

If 15a2+4b215a2-4b2=477 then find the value of following ratio. b3-2a3b3+2a3 - Algebra

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Question

If `bb((15a^2 + 4b^2)/( 15a^2 - 4b^2) = 47/7)` then find the value of following ratio.

`[ b^3 - 2a^3]/[ b^3 + 2a^3]`

Sum

Solution

`(15a^2 + 4b^2)/( 15a^2 - 4b^2) = 47/7`

Applying componendo and dividendo, we get

`[(15a^2 + 4b^2) + ( 15a^2 - 4b^2)]/[(15a^2 + 4b^2) - ( 15a^2 - 4b^2)] = [47 + 7]/[47-7]`

⇒ `[15a^2 + 4b^2 +15a^2 - 4b^2]/[15a^2 + 4b^2 - 15a^2 + 4b^2]` =`54/40`

⇒ `(30a^2)/(8b^2) = 27/20`

⇒ `a^2/b^2 = (27 xx 8)/( 20 xx 30) = 9/25`

⇒ `a/b = sqrt( 9/25) = 3/5`

` therefore    [ b^3 - 2a^3]/[ b^3 + 2a^3]`

Divided by `b^3`

=`[ b^3/b^3 - (2a^3)/b^3]/[ b^3/b^3 + (2a^3)/b^3]`

= `[ 1 - 2 xx 27/125]/[1 + 2 xx 27/125]`   ...`( a/b = 3/5 ⇒ a^3/b^3 = 27/125)`

= `[ (125  -  54)/125] /[(125  +  54)/125] `

=`71/179`

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Operations on Equal Ratios
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Chapter 4: Ratio and Proportion - Practice Set 4.3 [Page 70]

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Balbharati Algebra (Mathematics 1) [English] 9 Standard Maharashtra State Board
Chapter 4 Ratio and Proportion
Practice Set 4.3 | Q (2) (iv) | Page 70
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