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Question
If `bb(a/b = 7/3)` then find the value of the following ratio.
`(2a^2 + 3b^2)/(2a^2 - 3b^2)`
Solution
`a/b = 7/3`
Let the common multiple be k.
⇒ `a = 7k , b = 3k`
`therefore (2a^2 + 3b^2)/(2a^2 - 3b^2)`
= `(2 xx (7k)^2 + 3 xx (3k)^2)/(2 xx (7k)^2 - 3 xx (3k)^2)`
= `(98k^2 + 27k^2)/( 98k^2 - 27k^2)`
= `(125k^2)/(71k^2)`
= `125/71`
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