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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

If 2 = 1.414, 3 = 1.732, 5 = 2.236, 10 = 3.162, then find the values of the following correct to 3 places of decimals. 300+90-8 - Mathematics

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Question

If `sqrt(2)` = 1.414, `sqrt(3)` = 1.732, `sqrt(5)` = 2.236, `sqrt(10)` = 3.162, then find the values of the following correct to 3 places of decimals.

`sqrt(300) + sqrt(90) - sqrt(8)`

Sum

Solution

`sqrt(300) + sqrt(90) - sqrt(8) = sqrt(3 xx 100) + sqrt(9 xx 10) - sqrt(4 xx 2)`

= `10sqrt(3) + 3sqrt(10) - 2sqrt(2)`

= 10 × 1.732 + 3 × 3.162 – 2 × 1.414

= 17.32 + 9.486 – 2.828

= 26.806 – 2.828

= 23.978

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Chapter 2: Real Numbers - Exercise 2.6 [Page 68]

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Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 2 Real Numbers
Exercise 2.6 | Q 3. (ii) | Page 68
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