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Question
If a = 3, b = 0, c = 2 and d = 1, find the value of 6a − 3b − 4c − 2d
Sum
Solution
6a − 3b − 4c − 2d
= 6 × 3 − 3 × 0 − 4 × 2 − 2 × 1
= 18 − 0 − 8 − 2
= 18 − 10
= 8
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Concept of Substitution
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