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If the Extremities of the Diagonal of a Square Are (1, –2, 3 and (2, –3, 5), Then the Length of the Side is - Mathematics

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Question

If the extremities of the diagonal of a square are (1, –2, 3 and (2, –3, 5), then the length of the side is 

Options

  • \[\sqrt{6}\]  

  •  \[\sqrt{3}\]

  •  \[\sqrt{5}\] 

  •  \[\sqrt{7}\]

MCQ

Solution

 \[\sqrt{3}\] 

Length of the diagonal =

\[\sqrt{\left( 2 - 1 \right)^2 + \left( - 3 + 2 \right)^2 + \left( 5 - 3 \right)^2} = \sqrt{1 + 1 + 4} = \sqrt{6}\] 

∴ Length of the side = \[\frac{\text{ Length of diagonal }}{\sqrt{2}} = \frac{\sqrt{6}}{\sqrt{2}} = \sqrt{3}\]

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Three Dimessional Space
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Chapter 28: Introduction to three dimensional coordinate geometry - Exercise 28.5 [Page 22]

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RD Sharma Mathematics [English] Class 11
Chapter 28 Introduction to three dimensional coordinate geometry
Exercise 28.5 | Q 4 | Page 22
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