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Question
If l = 4pq2, b = −3p2q, h = 2p3q3 then, find the value of l × b × h
Solution
Given l = 4pq2
b = −3p2q
h = 2p3q3
l × b × h = (4pq2) × −3p2q × 2p3q3
= (+) (−) (+) (4 × 3 × 2) (p × p2 × p3) (q × q2 × q3)
= – 24p6q6
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