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If P(–b, 9a – 2) divides the line segment joining the points A(–3, 3a + 1) and B(5, 8a) in the ratio 3: 1, find the values of a and b. - Mathematics

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Question

If P(–b, 9a – 2) divides the line segment joining the points A(–3, 3a + 1) and B(5, 8a) in the ratio 3: 1, find the values of a and b.

Sum

Solution

Take (x1, y1) = (–3, 3a + 1); (x2, y2) = B(5, 8a)

And (x, y) = (–b, 9a – 2)

Here m1 = 3 and m2 =1

Coordinate of P(x, y) = `((m_1x_2 + m_2x_1)/(m_1 _ m_2), (m_1y_2 + m_2y_1)/(m_1 + m_2))`

`=> x = (m_1x_2 + m_2x_1)/(m_1 _ m_2)` and `y = (m_1y_2 + m_2y_1)/(m_1 + m_2)`

`=> -b = (3 xx 5 + 1 xx (-3))/(3 + 1)` and `9a - 2 = (3xx8a + 1(3a + 1))/(3 + 1)`

`=> -b = (15 - 3)/4` and `9a - 2 = (24a + 3a + 1)/4`

`=>` –4b = 12 and 36a – 8 = 27a + 1

`=>` b = –3 and 9a = 9

a = 1 and b = –3

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The Mid-point of a Line Segment (Mid-point Formula)
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Chapter 13: Section and Mid-Point Formula - Exercise 13 (A) [Page 178]

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Selina Mathematics [English] Class 10 ICSE
Chapter 13 Section and Mid-Point Formula
Exercise 13 (A) | Q 26 | Page 178
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