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Question
If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.
Solution
Emf of the battery, V = 20 V
Current (I1) flowing through resistor R1 is given by,
I1 = `"V"/"R"_1`
= `20/2`
= 10 A
Current (I2) flowing through resistor R2 is given by,
I2 = `"V"/"R"_2`
= `20/4`
= 5 A
Current (I3) flowing through resistor R3 is given by,
I3 = `"V"/"R"_3`
= `20/5`
= 4 A
Total current, I = I1 + I2 + I3 = 10 + 5 + 4 = 19 A
Therefore, the current through each resister is 10 A, 5 A, and 4 A respectively and the total current is 19 A.
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