Advertisements
Advertisements
Question
If we join a vertex to a point on opposite side which divides that side in the ratio 1:1, then what is the special name of that line segment?
Options
Median
Angle bisector
Altitude
Hypotenuse
Solution
Median
Explanation:
Consider ΔABC in which AD divides BC in the ratio 1:1.
Now, BD:DC = 1:1
⇒ `(BD)/(DC) = 1/1`
∴ BD = DC
Since, AD divides BC into two equal parts.
Hence, AD is the median.
APPEARS IN
RELATED QUESTIONS
The length of hypotenuse of a right angled triangle is 15. Find the length of median of its hypotenuse.
In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.
In the given figure, point S is any point on side QR of ΔPQR Prove that: PQ + QR + RP > 2PS
Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.
The centroid of a triangle divides each medians in the ratio _______
In any triangle the centroid and the incentre are located inside the triangle
In the given figure, A is the midpoint of YZ and G is the centroid of the triangle XYZ. If the length of GA is 3 cm, find XA
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
