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Question
If (x + a) is a factor of 2x2 + 2ax + 5x + 10, find a.
Solution
Given (x + a) is a factor of `f(x) = 2x^2 + 2ax + 5x + 10`.
Let us now divide `f(x)` by x + a .
We have,
Now, remainder = 0
` 10 - 5a = 0`
` 10 = 5a `
`10/5=a`
`2 =a`
Hence, the value of a is 2 .
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