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If `X = (Sqrt3 + 1)/2` Find the Value of `4x^2 +2x^2 - 8x + 7` - Mathematics

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Question

if `x =  (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7` 

Solution

We have `x = (sqrt3 + 1)/2`

It can be simplified as

`2x - 1 = sqrt3`

On squaring both sides, we get 

`(2x - 1)^2 = (sqrt3)^2`

`(2x)^2 + 1 - 2 xx 2x = 3`

`4x^2 + 1 - 4x = 3`

`4x^2 - 4x - 2 = 0`

The given equation can be rewritten as `4x^2 + 2x^2 - 8x + 7 = x(4x^2 - 4x - 2) + 3 + 7`

Therefore, we have 

`4x^3 + 2x^2 - 8x + 7 = x(0) + 6/4 (0) + 3 + 4`

= 3  + 7

= 10

Hence, the value of given expression is 10

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Chapter 3: Rationalisation - Exercise 3.2 [Page 15]

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RD Sharma Mathematics [English] Class 9
Chapter 3 Rationalisation
Exercise 3.2 | Q 12 | Page 15

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